Question

The emf of a driving cell in a potentiometer circuit is 100V. Its internal resistance is 10 ohm. Length of potentiometer wire is 200cm. A cell of emf 5V and internal resistance 0.1 ohm is balanced against 20cm length of the wire. The length against which a cell of emf 6V and internal resistance 0.2 ohm can be balanced is
(1) 24 cm
(2) 20 cm
(3) 22.5 cm
(4) 40 cm​

Answer 1

Answer:

E(5)/ E(6) = L/l

Explanation:

5/6 = 20 /l

l = (20 x 6 )/5

= 24cm.