Question

the emf of cell balances against length of 217 cm of potentiometer wire cell is shunted by resistance of 15 ohm the balancing length is 200 cm find internal resistance of cell​

Answer 1

ANSWER;

Internal Resistance=r

r=R (L1/L2-1)

•10 {L1/250-1}=5 {L1/200-1}

>L1{1000/3Cm}

and r=10

{1000/3×250-1}=10/3ohm.