Question

The emf of the following cell Cd/Cd

2+(0.002 M)// Cd

2+ (X M) /Cd is 0.061 V at

25 oC. Find the value of ‘X’. If water is added to anode, what happens to cell emf​

Answer 1

Answer:

(0.6M)|Fe at 25^∘ C .The standard reduction potential of Cd/Cdh2 + and Fe/Fe^2 ... The standard reduction potential of Cd/Cdh2+andFe/Fe2+ electrodes are -0.403 ... Given below are the half-cell reactions: ... 2(Mn3++e−→Mn2+); E∘=+1.51 V ... Calculate the standard EMF of the following cell Cd∣Cd2+∣∣Ag+∣Ag.

mark me as brainliest..