Question

The emf of the galvanic cell having representation
Pb/Pb2+(0.002 M)||Pb2+(0.02M)|Pb is
(Given, E° Pb2+/Pb =-0.13 V.)
(1) 0.03 V
(2) 0.12 V
(4) -0.12 V
(3) - 0.03 V​
Please explain

Answer 1

Answer:

The answer option 1 .....

Explanation:

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