Question

The emfof a Daniel cell is 1.08V, when the terminals of the cells are connected to a resistance of 3ohm,the potential difference across the terminals is found to be 0.6V, then the internal resistance of the cell is

Answer 1

potential drop across the external 3 ohm resistor = 0.60 V
current through it : 0.60 / 3 = 0.20 Amp

Potential Drop across the internal resistance = 1.08 - 0.60 = 0.48 V
internal resistance = 0.48 V / 0.20 A = 2.4 Ohms