The emitter current in a transistor is 4mA. If the leakage current is 6mA and α = 0.98, then find the collector current?
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Therefore Collector Current = 3.92 mA
Given:
The emitter current in a transister = 4 mA
Leakage Current = 6 mA
α = o.98
To Find:
The collector's current Ic
Solution:
We can simply solve this numerical problem by using the following process.
Given that
α = 0.98
The emitter current in a transistor Ie = 4 mA
Leakage Current = 6 mA
⇒ α = Ic/Ie = 0.98
Ic = 0.98 × 4 = 3.92
Therefore Collector Current = 3.92 mA
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