The emperical formula of boron hydride is BH3 .calculate molecular formula when the Measured mass of compound is 27.66(atomic Mass B =10.81 , H=1)
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The emperical formula of boron hydride is BH3 .calculate molecular formula when the Measured mass of compound is 27.66(atomic Mass B =10.81 , H=1)
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Solution:
the atomic mass is given by=B+3(H)=10.81+3(1)=13.81u
but the measured molecular mass for Boron atom is given as 27.66u
by using the expression Molecular formula=n×empricial formula
n=molecular formula/Empirical formula=27.66/13.81=2
cutting value of n = 2 in the Empirical formula we get molecular formula as
Molecular formula=2(BH3)=B2H6.
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