Question

the empirical formula if C=40%,H=13.3% and N=46.67%

Answer 1

C -40% -40/12 -10/3-10/3/(10/3)-1.
N-46.67% -140/3%-140/3/(14)-10/3-10/3/(10/3)-1.
H-13.33%-40/3%-40/3/(1)=40/3 -40/3/(10/3)-4.
CH4N is the Empirical Formula. First divide by mass of one mole of the element then divided by the least ratio.