The empirical formula of a compound is C4H3O2. Its vapour density is 83. What will be the molecular formula of the compound? (Atomic masses of C=12u, H=1u, O=16u)
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Answer:
i am not sure i am so sorry
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C8H6O4
Explanation:
Molecular formula=2.VD÷ empherical formula mass
=2*83÷48+3+32
= 166÷83
= 2
So, molecular formula=empherical formula*2
= C4H3O2*2
=C8H6O4
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