Question

The empirical formula of a compound is C4H3O2. Its vapour density is 83. What will be the molecular formula of the compound? (Atomic masses of C=12u, H=1u, O=16u)

Answer 1

Answer:

i am not sure i am so sorry

Answer 2

C8H6O4

Explanation:

Molecular formula=2.VD÷ empherical formula mass

=2*83÷48+3+32

= 166÷83

= 2

So, molecular formula=empherical formula*2

= C4H3O2*2

=C8H6O4