Question

The empirical formula of a compound is CH. It's molecular weight is 78. The molecular forrmulaof the compound will be?

Answer 1

n=molecular weight / Emperical weight 
n=  78/13 = 6
molecular formula = (CH)n  = C₆H₆

Answer 2

Answer:$C_6H_6$

Explanation:

Given: Empirical formula is $CH$  

The empirical weight of$CH$ = 1(12) + 1(1) = 13.

The molecular weight = 78 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}$

$n=\frac{78}{13}=6$

Thus molecular formula will be=${\text{Equivalent formula}}\times n=CH\times 6=C_6H_6$