the empirical formula of an organic compound containing carbon and hydrogen is ch2 the mass of 1 litre of this organic gas is exactly equal to that of 1 litre of N2 at same temperature and pressure therefore the molecular formula of the organic gas is
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At normal temperature and pressure,
22.4L of N2 has a mass of 28g
So, 1L =28/22.4 g.
Let the mass of organic compound whose volume is 22.4L =X g
Then mass of 1L of that compound =X/22.4
Now, given that the mass of 1L of N2 and organic compound are same.
28/22.4 = X/22.4
X=28
Empirical formula is CH2
Empirical formula mass =12+2=14
So molecular mass is =X=28
Therefore n factor = 2
So molecular formula is C2H4
The organic compound is ethene.
Hope this helps you.
22.4L of N2 has a mass of 28g
So, 1L =28/22.4 g.
Let the mass of organic compound whose volume is 22.4L =X g
Then mass of 1L of that compound =X/22.4
Now, given that the mass of 1L of N2 and organic compound are same.
28/22.4 = X/22.4
X=28
Empirical formula is CH2
Empirical formula mass =12+2=14
So molecular mass is =X=28
Therefore n factor = 2
So molecular formula is C2H4
The organic compound is ethene.
Hope this helps you.
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16
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