the empirical formula of compound is CO2H .1.8 g of this compound in gaseous state occupies 448 cm^3 at S.T.P find its molecular formula
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Explanation:
7 hours ago · 2 answers
1.8 g of this compound in gaseous state occupies 448 cm^3 at S.T.P find its molecular formula. 2. See answers.
Answered by
1
Answer:
C2O4H2
Explanation:
- convert cm³ into dm³ . 448/1000=0.448dm³
- find moles from volume = 0.448/22.4=0.02 moles
- divide moles from mass =1.8g/0.02moles=90 g/moles ( molecular formula mass)
- divide molecular formula mass from emperical formula mass which is 45.90/45=2 now multiply emperical formula by 2 so the molecular formula will be
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