Question

the empirical formula of compound is CO2H .1.8 g of this compound in gaseous state occupies 448 cm^3 at S.T.P find its molecular formula

Answer 1

Explanation:

C

2

H

4

The density is 1.25 g/L.

∴ 1 L ≡ 1.25 g.

As we know that 22.4 L corresponds to 1 mole of a gas,

22.4 L ≡ 1.25×22.4=28= Molecular weight.

Let the Molecular Formula be C

x

H

2x

So, 28=12x+2x=14x.

we get, x=2

Therefore, the compound is (CH

2

)

x

=C

2

H

Answer 2

Answer:

C

2

Explanation:

H

4

I think it is correct