Question

the empirical formula of gaseous compound is ch2 the density of components 1.25 gram per litre at STP molecular formula pasta compound of the compound

Answer 1

Answer:

Molecular formula = C₂H₄

Explanation:

Given data:

Density = 1.25 g/L

Empirical formula = CH₂

Molecular formula = ?

Solution:

PM = dRT

M = d RT /P

M = 1.25 g/L × 0.0821 atm. L. K⁻¹ . mol⁻¹ × 273 K / 1 atm

M = 28.02 g.mol⁻¹

Molecular formula:

Molecular formula = n( empirical formula)

n = Molecular mass / empirical formula mass

n = 28.02 / 14

n = 2

Molecular formula = n( empirical formula)

Molecular formula = 2(CH₂)

Molecular formula = C₂H₄

Answer 2

Answer:

C2H4

Explanation:

molecular formula= 22.4*1.25=28g

=n= molecular formula weight / emphirical formula weight

n=28/14

=2

=2(CH2)

=C2H4