The (+) enantiomer of compound D has an optical rotation of 25°. If a pure sample of D contains 80% of the (+) enantiomer and 20%
of the (-) enantiomer, what is the optical rotation value?
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Answer:
15°
Explanation:-
- PURE=25°
- % Major = 80%
- % Minor = 20%
Optical Purity = X/25 = 80-20 = 60%
Solve for X
- X = 15°
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