Chemistry, asked by akaa5425, 1 month ago


The (+) enantiomer of compound D has an optical rotation of 25°. If a pure sample of D contains 80% of the (+) enantiomer and 20%
of the (-) enantiomer, what is the optical rotation value?

Answers

Answered by astitwajha
2

Answer:

15°

Explanation:-

  • PURE=25°

  • % Major = 80%
  • % Minor = 20%

Optical Purity = X/25 = 80-20 = 60%

Solve for X

  • X = 15°
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