Question

The end of two rods of different materials with their thermal conductivities, area of cross-section and lengths all are in the ratio 1 : 2 are maintained at the same temperature difference. If the rate of flow of heat in the first rod is 4 cal s', then in the second rod rate of heat flow in cal/s will be ​

Answer 1

Answer:

Here , Q

1

=

l

1

K

1

A

1

(θ

1

−θ

2

)

and Q

2

=

l

2

K

2

A

2

(θ

1

−θ

2

)

∴

Q

1

Q

2

=

K

1

K

2

×

A

1

A

2

×

l

2

l

1

=2×2×

2

1

=2

so, Q

2

=2Q

1

=2×4=8 cal/s