The end points of an edge of a cube are (0,0) and (4,0). Find lateral surface area of cube and length of
the diagonal of its face.
Answers
Step-by-step explanation:
Given:-
The end points of an edge of a cube are (0,0) and (4,0).
To find:-
Find lateral surface area of cube and length of the diagonal of its face.
Solution:-
The end points of an edge of a cube are (0,0) and (4,0)
Let (x,y)=(4,0)=>x=4;y=0
(0,0)= The origin
The distance from the origin to the point (x,y) is √(x²+y²) units
=>√(0²+4²)
=>√(0+16)
=>√16
=>4 units
The distance is 4 units
The length of the edge of the cube = 4 units
1)Lateral surface area of a cube :-
The edge of a cube is "a" units then the lateral surface area of a cube is 4a² sq.units
we have a= 4 units
Lateral surface area = 4(4²)
=>4×4×4
=>64 sq.units
Lateral surface area of the cube = 64 sq.units
2)Length of the diagonal of the face:-
The edge of a cube is "a" units then the length of the diagonal is √3× length of the side=√3 a units
=>Diagonal =4(√3) units
Length of the diagonal = 4√3 units
Answer:-
1) Lateral surface area of the cube = 64 sq.units
2) Length of the diagonal of the face of the cube = 4√3 units
Used formulae:-
The edge of a cube is "a" units then ,
- Lateral surface area = 4a² sq.units
- Length of the diagonal = √3 a units
The distance between the origin (0,0) and the point (x,y) is √(x²+y²) units