the end term of an ap is 5n + 3 e and the Fourth term is
Answers
Answered by
7
Step-by-step explanation:
Correct option is
B
245
Given, a
n
=5n−3
Put n=1, a
1
=5−3=2
Put n=10, a
10
=5×10−3=47
Sum =
2
n
(a+l)
=
2
10
(2+47)
= 49×5
=245
Answered by
3
Answer:
245
Given, a
n
=5n−3
Put n=1, a
1
=5−3=2
Put n=10, a
10
=5×10−3=47
Sum =
2
n
(a+l)
=
2
10
(2+47)
= 49×5
=245
Step-by-step explanation:
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