Question

The endpoints of a diameter of circle are (4 3) and (- 2 ,-1) then radius of the circle is

options

4√3

2√13

√13

5√13​

Answer 1

Answer:

third option I correct

Answer 2

Answer:

2√13

Step-by-step explanation:

$diameter = \sqrt{(4+2)^{2} +(3+1)^2}\\diameter = \sqrt{52} = 4\sqrt{13} \\radius = 2\sqrt{13}$