Question

the ends of a diagonal of a square have coordinates (-2, p) and (p, 2). find p, if the area of the square is 40 square units.

Answer 1

this is the answer of ur question

Answer 2

Answer:

p = 6

Step-by-step explanation:

Area of square =$Side ^2$

So,$Side ^2=40$

$Side =\sqrt{40}$

$Side =2\sqrt{10}$

Length of diagonal of square = $\sqrt{2}a=\sqrt{2}(2\sqrt{10})=2\sqrt{20}$

Coordinates of (-2,p) and (p,2)

Formula : $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(p+2)^2+(2-p)^2}$

$d=\sqrt{p^2+4+4p+4+p^2-4p}$

$d=\sqrt{2p^2+8}$

$p=6$

Hence the value of p is 6