Question

The ends of a rod of length ( moves on two mutually perpendicular lines. The locus of point on
the rod which divides it in the ratio 1:2 is ar? + bv=cf, then a +b+c=​

Answer 1

Answer:

ends of a rod of length ( moves on two mutually perpendicular lines. The locus of point on

the rod which divides it in the ratio 1:2 is ar? + bv=cf, then a +b+c= search in socratic