The ends of the hypotenuse of a right angled triangle are (0,6) and (6,0). Find the equation of
the locus of its third vertex.
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Answer:
x^2+y^2-6x-6y=0
Step-by-step explanation:
Let ABC is a right angled triangle whose hypotenuse is
AC and angle B=90°
coordinate A(6,0) C(0,6)
Let coordinate of B (h,k)
slope of BA (M1)=(0-K)/(6-h)
slope of BC (M2)=(6-K)/(0-h)
Angle between BA and BC Is 90°.
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