Question

the energies of activation for forward and reverse reaction for a2 +b2 reversible 2ab are 180 kj / mol and 200kj / mol respectively. the presence of a catalyst lowers the activation energy of both reactions by 100kj / mol .the enthalpy change of the reaction (a2 + b2 gives 2ab ) in the presence of catalyst will be

Answer 1

Answer:

-20 kJ/mol

Explanation:

Enthalpy change is constant irrespective of catalyst and is equal to Activation E forward - backward = 180 - 200 = -20 kJ/mol

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Answer 2

Answer:

Explanation:

ΔHR = Ef - Eb = 180 - 200 = - 20 kJ mol–1. The correct answer for this question should be –20kJ mol– 1.