Question

• The energy acquired by a charge of 1 C while moving
through a potential difference of 1 volt is
(a) 1-6 J
(b) 1-6 X 1019)
(c) 1.6 X 10-19 J (d) 1-6 x 10-21 J​

Answer 1

Given:

Charge on given particle,q= 1 C

Potential difference,V= 1 V

To Find:

The energy acquired pr work done by the charge

Solution:

We know that,

• Relation between potential difference, work done(energy acquired) and magnitude of charge is given by

$\pink{\underline{\boxed{\bf{V=\frac{W}{q}}}}}$

where,

V is the potential difference

W is work done

q is magnitude of charge

━━━━━━━━━━━━━━━━━━━━━━━━━

Let the energy acquired by electron be W

So,

$\longrightarrow\rm{V=\dfrac{W}{q}}$

$\longrightarrow\rm{1=\dfrac{W}{1}}$

$\longrightarrow\rm{1=W}$

$\longrightarrow\rm\green{W=1J}$

Hence, the energy acquired by charge of 1 C through the potential difference of 1 V is 1 J.

Answer 2

Answer:

Given and Find:

• The energy acquired by a charge of 1 C while moving through a potential difference of 1 volt is.

Using formula:

• Potential difference = Work done/Magnitude.

Calculations:

⇢ 1 = Work done/1

⇢ 1 = Work done

⇢ W = 1 Joule

Therefore, 1 Joule is the required work done.