Question

The energy change in kilojoules per mole when lithium atoms lose an electron to bromine atoms to form isolated Li+ and Br- ions. [The Ei for Li(g) is +520 kJ/mol;   the Eea for Br(g) is -325 kJ/mol.]​

Answer 1

Answer:

I dont know about this sorry

Explanation:

by the way thank you for the free points

Answer 2

Answer:

The energy change in KJ per mole for formation of isolated ions is +195KJ/mole .

Explanation:

Given that : $Li(g)$   →  $Li^{+} + e^{-}$    and    $Br(g) + e^{-}$  →  $Br^{-}$

 $E_{i} (Li)= +520KJmol^{-1}\\ E_{a} (Br)= -325KJmol^{-1}$

Energy Change = Ionization energy + electron affinity

ΔE = $E_{i} + E_{a}$

ΔE $= [(520)+(-325)] KJmol^{-1}$

ΔE =  $+195KJmol^{-1}$

Therefore the energy change to form isolated ions  Li⁺ and  Br⁻ is +195KJ/mole.