Chemistry, asked by SwayamjeetBehera, 7 months ago

The energy difference between two electronic states is 399.1 Kj mol -1.Calculate the wavelength and frequency of light emitted when an electron drops from a higher to a lower state.plancks constant =6.6262 *10^-34Js.

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Answered by satyamrana15jan

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Explanation:

A sunlight has a maximum intensity at a wavelength of about 6.0 x 107m. ... frequency range = 7.5 x 10's to 4.0 × 101*s- Ans. 12.7 PLANCK'S QUANTUM THEORY Energy ... The energy difference between two electronic states is 399.1 kJ mol. ... frequency of light emitted when an electron drops from a higher to a lower state

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The energy difference between two electronic states is 399.1 Kj mol -1.Calculate the wavelength and frequency of light emitted when an electron drops from a higher to a lower state.plancks constant =6.6262 *10^-34Js.​

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The energy difference between two electronic states is 399.1 Kj mol -1.Calculate the wavelength and frequency of light emitted when an electron drops from a higher to a lower state.plancks constant =6.6262 *10^-34Js.