Question

The energy difference between two electronic states is 46 .12 kcal /mole. What will be the frequency of
the light emitted when an electron drops from the higher to the lower energy state

(Planck' constant = 9.52 x 10-14 kcal sec mole -1)​

Answer 1

Answer:

energy= planck's constant*frequency

frequency=46.12×10^3/9.52×10^-14=4×10^17 sec^-1

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Explanation:

Answer 2

Answer:

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