Question

The energy E of a particle at position x at time t is given byE=a/t(b+x^2)where a and b are constants. The dimensional formula of a is

MLT-1

ML2T-1

ML4T-1

ML3T-1

​

Answer 1

Explanation:

here is the answer dear...... please mark me as brainliest pllzzzzzzz and follow me........

Answer 2

Answer:

The correct answer is $ML^{4}T^{-1}$.

Explanation:

Dimensional formula of $x^{2}$ = $L^{2}$

The dimensional formula of b is equal to the dimensional formula of $x^{2}$ because they are in addition.

Dimensional formula of b = $L^{2}$

By the given equation,

$E=\frac{a}{t(b+x^{2}) }$

Dimensional formula of a = Dimensional formula of t × Dimensional       formula of E × dimensional formula of b

                                          = T×$ML^{2}T^{-2}$×$L^{2}$

                                          = $ML^{4}T^{-1}$

So, the dimensional formula of a is $ML^{4}T^{-1}$.