Question

the energy evolved in a nuclear fission reaction is of the order of .......??​

Answer 1

Answer:

The answer of the following question is Option C.

Explanation:

The energy evolved in a nuclear fission reaction is of the order of 10.10 Mev.

Nuclear Fission

- It is a phenomena where nucleus of an atom splits into two or more small nuclei.

Example of equation-

$23592U+10n→14456Ba+8936Kr+310n+210MeV$

To find the energy of order reaction:

The atomic masses are-

m(238U)=238.050784u,

m(95Sr)=94.919388u,

m(140Xe)=139.921610u, and

m(n)=1.008665u.

The energy released is =  mass destroyed times c2,

Now we find the difference in mass between the parent 238U and the fission products.

the mass is =237.866993u.

Δm=238.050784u−237.8669933u=0.183791u.