Chemistry, asked by Shrutikabhujbal2208, 8 months ago

The energy evolved in a nuclear reaction is of th order of

Answers

Answered by Anonymous
10

Answer:

The energy harnessed in nuclei is released in nuclear reactions. Fission is the splitting of a heavy nucleus into lighter nuclei and fusion is the combining of nuclei to form a bigger and heavier nucleus. The consequence of fission or fusion is the absorption or release of energy.

Answered by mad210202
0

Answer:

The answer of the following question is 10.10 Mev.

Explanation:

The energy evolved in a nuclear fission reaction is of the order of 10.10 Mev.

Nuclear Fission

- It is a phenomena where nucleus of an atom splits into two or more small nuclei.

Example of equation-

23592U+10n→14456Ba+8936Kr+310n+210MeV

To find the energy of order reaction:

The atomic masses are-

m(238U)=238.050784u,

m(95Sr)=94.919388u,

m(140Xe)=139.921610u, and

m(n)=1.008665u.

The energy released is =  mass destroyed times c2,

Now we find the difference in mass between the parent 238U and the fission products.

the mass is =237.866993u.

Δm=238.050784u−237.8669933u=0.183791u.

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