Question

The energy flux of sunlight reaching the surface of the earth is 1.388 × 103 W/m2. How many photons are incident on the Earth per second/square meter? Assume an average wavelength of 730 nm.​

Answer 1

Answer:

Therefore, every second, 3.84 x 1021 photons are incident per square metre on earth.

Answer 2

Index :-

$N_P=Number\ of\ incident\ photons$

$h=Plancks\ Constant$

$c=Speed\ of\ light$

${\lambda}=Incident\ wavelength$

$T=Time$

$A=Area$

$I=Intensity\ of\ sunglight\ reaching\ on\ the\ earth\ surface$

Solution :-

Energy flux is equivalent to intensity.

Intensity of sunlight reaching the earth surface (I) is

$=\frac{(Number\ of\ photons\ emitted)(Energy\ of\ 1\ photon)}{(Time)(Area)}$$=\frac{(Number\ of\ photons\ emitted)(\frac{hc}{ \lambda }) }{(Time)(Area)}$

$=\frac{(N_P)(\frac{hc}{\lambda}) }{(T)(A)}$

$=>N_P=\frac{(I)(T)(A)(\lambda)}{hc}$

$=>N_P=\frac{((1.388\times10^3)W/m^2)((1)s)((1)m^2)((730)nm)}{((1240)eV.nm)}$

$=>N_P=5.10\times10^{21}$

Hence, number of photons incident on the Earth per second/square meter are 5.10 × 10²¹.

Remarks :-

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