Question

the energy(in eV) possessed by neon atom at 27 degree Celsius
1) 1.72×10^-3
2)4.75×10^-4
3)3.88×10^-2
4)3.27×10^-5

Answer 1

Answer:

Explanation:

=> The energy(in eV) possessed by neon atom at 27 degree Celsius:

Kb = 1.38 * 10⁻²³

T = 300

E = ?

=> Thus, the energy, E :

E = 3/2 KbT

= 3/2 * 1.38 * 10⁻²³ * 300

= 6.21 * 10⁻²¹ J

=  6.21 * 10⁻²¹ * 6.24 * 10¹⁸ eV

= 0.0388 eV

= 3.88 * 10⁻²

Answer 2

Answer:

hope u understand

Explanation:

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