The energy levels of hypothetical one electron atom
are :
O eV - n =
- 0.50 eV - n = 5
- 1.45 eV – n = 4
- 3.08 eV – n = 3
- 5.3 eV – n = 2
15.6 eV - n = 1
Choose the correct options
The ionisation potential of atom
is 15.6 eV
The short wavelength limit of the
series terminating at n = 2 is
233.9 nm
The wave no. of photon emitted
for the transition made by the
electron from third orbit to its
orbit is 1.009 x 107 m-1
The ionisation potential of atom
is 25.6 Ev
Answers
Answered by
0
Answer:
I can help help you but you have to make me as a brainliest answer please
Similar questions