Question

The energy liberated in the fission of a single uranium 235 atom is 3.2x10-11 calculate the power corresponding to fission of i gmof uranium per day (N = 6,023 x 10°/mole​

Answer 1

Answer:

the energy released by fission of 1 g of uranium 235 atom is shown there....

Answer 2

2.276*10^4 kWhr

Given,

energy liberated in the fission of a single uranium  235 atom is=3.2x10-11

number of atoms (N)=6.023 x 10^23

To Find,

Energy released in fission

Solution:

number of atoms in 1 g of 235U(N)=6.023*10^23/235

N=2.56*10^21 atoms

Energy released in fission of 1 kg of 235 atom (E)=N*$N_{E1}$

=2.56*10^21*3.2*10^-11

=8.192*10^10 j

=8.192*10^10/1000*60*60 kWhr

=2.276*10^4 kWhr

Hence the Energy released in fission of 1 kg of 235 atom=2.276*10^4 kWhr

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