Question

The energy needed to remove the one electron from neutral helium atom is 24.6 eV. Then the energy needed to remove both the electrons from neutral helium atom is
(a) 79.0 eV
(b) 51.8 eV
(c) 49.2 eV
(d) 38.2 eV

Answer 1

Answer : (a) 79.0 eV

On removing an electron the Helium atom becomes a single electron atom, applying Bohr's Model, the energy of the single electron is given by 
$- 13.6 {z}^{2} \div {n}^{2}$
(where z is atomic no. and n is the no. of the shell in which the electron resides). 

Thus ,
the energy comes out to be -13.641, which is -54.4.

So ,
the total energy required to remove both the electrons will be 
24.6+54.4=79.0
$24.6 + 54.4 = 79$

Answer 2

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☸ Required Answer is :-


✨ a). 79


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