Question

The energy of a hydrogen atom in the ground state is – 13.6 eV.
The energy of a He⁺ ion in the first excited state will be
(a) –13.6 eV (b) – 27.2 eV
(c) – 54.4 eV (d) – 6.8 eV

Answer 1

Answer:

(a) is the correct answer.......

Answer 2

Answer:

-13.6eV

Explanation:

IE of helium = IE of hydrogen × Z^2 / n^2

IE of helium = -13.6 × 4 / 4

IE of helium = -13.6 eV

Hope this answer is helpful.