The energy of a hydrogen atom in the ground state is
– 13.6 eV. The energy of a He+ ion in the first excited state
will be
(a) –13.6 eV (b) – 27.2 eV
(c) – 54.4 eV (d) – 6.8 eV
Answers
Answered by
4
Answer:
(a)-13.6 eV
Explanation:
For the first excited state (n = 2), the energy of He+ ion (with Z = 2) will be - 13.6 eV. This is same as the ground state energy of a hydrogen atom. Similarly, for all the hydrogen like ions, the energy of the (n - 1)th excited state will be same as the ground state energy of a hydrogen atom if Z = n.
Answered by
0
Answer:
Answer will be (a) –13.6
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