Question

the energy of a photon is 3×10^-12ergs.what is the wavelength in nm ?(h=6.62×10^-27erg.sec;c=3×10^10cm.s^-1

Answer 1

1 ergs = 10^-7 Joule

1 cm = 10^-2 meter
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Energy of proton = E = 3×10^-12 ergs = 3×10^-19 J

Planck's constant = h = 6.62×10-27 ergs = 6.62×10-34 Js

speed of light = 3×10^10 cm = 3×10^8 m

wavelength = a = ?
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E = hc/a

Ea = hc

a = hc/E

a = 6.62×10^-34×3×10^8/3×10^-19

a = 6.62× 10^-34+8/10^-19

a = 6.62×10^-26/10^-19

a = 6.62×10^-26-(-19)

a = 6.62×10^-26+19

a = 6.62×10^-7 m

(1 nm = 10^-9 m )

a = 6.62×10^-7/10^-9

a = 6.62×10^-7+9

a = 6.62 × 10^-2 nm
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so wavelength = a = 6.62 × 10^-2 nm

Answer 2

Answer:

hey mate up explanatory is correct but the answer is 662 thank u for explaining

Explanation:

hope it helps