Chemistry, asked by snasha2020, 6 months ago

The energy of a photon of radiation having a wavelength of 300nm is ???

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Answered by Anonymous

1

E = hvλ

=6.626×10−−34×3×108300×10−9

=6.63×10−19J

Answered by krs1000024519

1

Answer:

I HOPE ITS HELPFUL.

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