Question

the energy of a photon that has a frequency of 1.821 x 10^16 s^-1 is

Answer 1

Answer:

u know that E = h.f , and h is planck constant: 6.6x10^-34

so, E= 6.6x 10^-34 . 18.21x10^15

E= 1.21x10^-17 J, the right answer is d

hope it helps u ;)

Answer 2

Answer:

The energy of the photon is $1.21*10^{-17} J$.

Explanation:

According to Planck's quantum theory, the photon is assumed to have wave character. The formula of energy is-

$E=hv$

where,

$v$ is the frequency of the wave (Hz)

$h$ is the Planck's constant ($6.63*10^{-34}m^{2}kg s^{-1}$)

We have the frequency- $1.821*10^{16} s^{-1}$

By substituting the values, we get-

$E = (6.63*10^{-34})*(1.821*10^{16})$

$E=1.21*10^{-17} J$ in the photon.