Question

the energy of an alpha particle is 1.2*10^-13 j. upto what closest distance can it reach the nucleus of silver (z=47)?​

Answer 1

Answer:

1.8 * 10^-13 m

Explanation:

Given,

The energy of an alpha particle is 1.2*10^-13 J

Z (silver) = 47

To find: upto what closest distance can it reach the nucleus of silver (z=47)

Solution:

The distance of closest appraoch can be found by the given formula,

r = 2Ze(2e) / 4πε₀mv²

Putting the values and on solving,

We will get r = 1.8 * 10^-13 m

Therefore, closest distance can alpha particle reach the nucleus of silver= 1.8 * 10^-13 m