The energy of an alpha particle is 6.8 into 10 raise to power minus 18 joule what will be the wavelength associated with it
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Given conditions ⇒
Energy of the Alpha Particles (E) = 6.8 × 10⁻¹⁸ J.
According to the Question, We need to find the Wavelength.
∴ Using the Formula,
E = hc/λ
where, λ = wavelength, h = Plank Constant = 6.63 × 10⁻³⁴ J-s., c = speed of the light in air = 3 × 10⁸ m/s.
∴ λ = hc/E
= (6.63 × 10⁻³⁴ × 3 × 10⁸) ÷ (6.8 × 10⁻¹⁸)
= 2.925 × 10⁻⁸ m
Hence, the wavelength is 2.925 × 10⁻⁸ m.
Hope it helps.
Energy of the Alpha Particles (E) = 6.8 × 10⁻¹⁸ J.
According to the Question, We need to find the Wavelength.
∴ Using the Formula,
E = hc/λ
where, λ = wavelength, h = Plank Constant = 6.63 × 10⁻³⁴ J-s., c = speed of the light in air = 3 × 10⁸ m/s.
∴ λ = hc/E
= (6.63 × 10⁻³⁴ × 3 × 10⁸) ÷ (6.8 × 10⁻¹⁸)
= 2.925 × 10⁻⁸ m
Hence, the wavelength is 2.925 × 10⁻⁸ m.
Hope it helps.
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