Question

The energy of an atom in ground state is
-3.4 eV. The ionisation energy of this atom
is :
(A) 1.7 eV
(B) 6.8 eV
1C) 3.4 eV
(D) 5.1 eV​

Answer 1

Answer:

c) 3.4

Explanation:

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Answer 2

Answer:

The Ionisation energy of the atom is 3.4 eV.

The correct answer is option (C).

Explanation:

The ionization energy of an atom is the energy required to remove an electron from an atom or molecule in its ground state.

When an electron is removed from an atom in its ground state, the resulting ion will have zero net energy, and the energy required to do so is equal to the difference between the energy of the ion and the energy of the neutral atom in its ground state.

Here it is given that the energy of the atom in its ground state is -3.4 eV. The ionization energy required to remove an electron from this atom can be written as

Ionization Energy = Energy of Ion - Energy of Atom

The energy of the ion will be zero as it is losing electron when it's in ground state and becomes positively charged.

Ionization Energy $= |0-3.4 eV| = 3.4 eV$

Therefore, the Ionisation energy of this atom is 3.4 eV.

To know more about Ionisation energy go to the following link.

https://brainly.in/question/13686323

To know more about atom go to the following link.

https://brainly.in/question/63665

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