The energy of an electron in the first Bohr or bit of h atom is -13.6ev. The possible energy value of excited state for electron in Bohr orbits of hydrogen
Answers
Answered by
9
Kinetic energy of electron kze2/2r
Potential energy of electron -kze2/r
=> P.E=−2(K.E)
Total energy = P.E +K.E
=−2E.E+K.E
=−KE= 13.6 ev
please like my answer thank and give brainliest remark
Potential energy of electron -kze2/r
=> P.E=−2(K.E)
Total energy = P.E +K.E
=−2E.E+K.E
=−KE= 13.6 ev
please like my answer thank and give brainliest remark
Similar questions