Question

The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value
(s) of the excited state (s) for electron in Bohr orbit of hydrogen is (are)
(A) -3.4 eV
(B) -4.2 eV
(C) -6.8 eV
(D) +6.8 eV​

Answer 1

Answer:

Explanation:

Since, FORMULA

E(n th shell) = (energy of 1st shell of H atom )*(zsq/nsq) ev

Energy for nth orbit or (n-1)th excited state = -13.6(1sq/nsq) ev

Put n=2

E= -13.6(1/4)ev

E= -3.4ev

Answer 2

Answer:

-3.4 ev

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