Question

the energy of an electron in the first orbit of hydrogen is -13.6 EV possible energy







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Answer 1

Answer:

The energy of an electron in the first orbit of He+ is ... energy of the electron in the first orbit of hydrogen would be ... and energy for H atom of first orbit =−2.18×10−18J .

Explanation:

The energy of an electron in the n−th orbit of H-atom is given by,

E

n

=−13.12×10

5

×

n

2

1

J

For first excited state, n=2

⇒E

n

=

4

−13.12×10

5

⇒E

n

=−3.28×10

5

J

Answer 2

it's orbit is given by formula

n

2

−13.6

eV.

Initial Energy of Electron = −13.6eV (Given that atom in i's ground state i.e n=1)

Energy after striking = (−13.6+12.09)eV=−1.51eV

⇒

n

2

−13.6

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eV=1.51eV ⇒ n

2

=9 ⇒ n=3.

So, hydrogen atom is excited to third state.