The energy of an electron in the nth Bohr orbit of hydrogen atom is
(a) –13.6 eV
n⁴
(b)–13.6 eV
n³
(c)– 13.6 eV
n²
(d) – 13.6 eV
n
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(c) – 13.6eV / n²
Explanation:
The energy of an electron in Bohr’s orbit of hydrogen atom is given by the expression:
En = 2π²me^4Z² / n²h²(4π∈0)² = -13.6Z²eV / n²
Since Z = 1 for hydrogen above equation can be further simplified to:
En = -13.6 eV / n²
Option C is the answer.
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