Question

The energy of an object of mass 'N'Djamena moving with a velocity of 5m/s is 25j. Calculate it's kinetic energy when the velocity is doubled

Plzz answer this question qick

Answer 1

Kinetic energy of an object is 25 j. Velocity is 5 m/s what will be its kinetic energy if velocity is doubles?

Answer

The kinetic energy of body is

100 J

.

kinetic energy

=

1

2

×

m

×

v

2

=

25 J

v

=

5 m/s

Let the mass of body be

m

.

1

2

×

m

×

v

2

=

25

m

×

5

2

=

50

m

×

25

=

50

m

=

50

25

or

m

=

2 kg

Now if velocity is doubled then

v

'

=

2

⋅

v

v

'

=

2

×

x

5

v

'

=

10 m/s

The final kinetic energy

=

1

2

×

m

×

(

v

'

)

2

=

1

2

x

×

2

x

×

10

2

=

1

2

x

×

2

x

×

100

=

100

J

Answer 2

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ANSWER :

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The mass of the object, m = m kg

The speed of the object, v = 5 m/s

The Kinetic Energy, K.E = 25 J

We know that ,

$kinetic \: energy = \frac{1}{2} mv ^{2}$

From this ,,,

Kinetic Energy ,K.E = 1/2 × m× (5)^2

25 = 1/2 × m × 25

m = 2 kg

(i) Now the Velocity of the object is doubled,,

v2 = 2v1

= 2( 5)

v2 = 10 m/s

Kinetic Energy, K.E = 1/2 × m × (v2)^2

= 1/2 × 2 × 10^2

= 100 J

The Kinetic Energy is 100 J.

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