The energy of electron in first bohr's orbit of hydrogen atom is -13.6 ev what will be its potential energy in n is equal to fourth orbit
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Answered by
13
Answer:
-3.4 eV
Explanation:
The energy of electron in nth orbit is calculated by the formula
E = -13.6 Z²/n² eV, where Z is the atomic mass and n is the no. of the orbit.
So in the 4th orbit of hydrogen atom,
⇒ E = -13.6* 1²/2² eV
⇒ E = -13.6 /4 eV
⇒ E = -3.4 eV
Answered by
4
Answer:
answer is as -1.70 ev
Explanation:
please see the answer above
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