Question

The energy of electron in the excited state is -0.85.If 'h' is the planck's constant then the Ngular momentum of the electron at the excited state is ____

Answer 1

angular momentum = nh/2π
energy of the excited electron = -0.85
then n = 4
mvr = 4×6.626×10^-34/(2×3.14)
=4.22 ×10^-34

Answer 2

$E_n = - 13.6 \frac{ {z}^{2} }{ {n}^{2} } \\ \\ z \: = 1 \\ \\ - 0.85 = \frac{ - 13.6}{ {n}^{2} } \\ \\ {n}^{2} = \frac{ - 13.6}{ - 0.85} \\ \\ {n}^{2} = 16 \\ n = \sqrt{16} \\ n = 4$

Angular momentum

$mvr= \frac{nh}{2\pi} \\ \\ mvr= \frac{4h}{2\pi} \\ \\ mvr = \frac{2h}{\pi}$